0=18t^2-72

Solution for 0=18t^2-72 equation:

0=18t^2-72

We move all terms to the left:

0-(18t^2-72)=0

We add all the numbers together, and all the variables

-(18t^2-72)=0

We get rid of parentheses

-18t^2+72=0

a = -18; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·(-18)·72
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-18}=\frac{-72}{-36}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-18}=\frac{72}{-36}
=-2
$